[3(x-4)]+[5(x+4)]=

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Solution for [3(x-4)]+[5(x+4)]= equation:


Simplifying
[3(x + -4)] + [5(x + 4)] = 0

Reorder the terms:
[3(-4 + x)] + [5(x + 4)] = 0
[(-4 * 3 + x * 3)] + [5(x + 4)] = 0
[(-12 + 3x)] + [5(x + 4)] = 0
[-12 + 3x] + [5(x + 4)] = 0

Remove brackets around [-12 + 3x]
-12 + 3x + [5(x + 4)] = 0

Reorder the terms:
-12 + 3x + [5(4 + x)] = 0
-12 + 3x + [(4 * 5 + x * 5)] = 0
-12 + 3x + [(20 + 5x)] = 0
-12 + 3x + [20 + 5x] = 0

Remove brackets around [20 + 5x]
-12 + 3x + 20 + 5x = 0

Reorder the terms:
-12 + 20 + 3x + 5x = 0

Combine like terms: -12 + 20 = 8
8 + 3x + 5x = 0

Combine like terms: 3x + 5x = 8x
8 + 8x = 0

Solving
8 + 8x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 8x = 0 + -8

Combine like terms: 8 + -8 = 0
0 + 8x = 0 + -8
8x = 0 + -8

Combine like terms: 0 + -8 = -8
8x = -8

Divide each side by '8'.
x = -1

Simplifying
x = -1

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